4c^2-19c=5

Solution for 4c^2-19c=5 equation:

Simplifying
4c2 + -19c = 5

Reorder the terms:
-19c + 4c2 = 5

Solving
-19c + 4c2 = 5

Solving for variable 'c'.

Reorder the terms:
-5 + -19c + 4c2 = 5 + -5

Combine like terms: 5 + -5 = 0
-5 + -19c + 4c2 = 0

Factor a trinomial.
(-1 + -4c)(5 + -1c) = 0

Subproblem 1
Set the factor '(-1 + -4c)' equal to zero and attempt to solve:

Simplifying
-1 + -4c = 0

Solving
-1 + -4c = 0

Move all terms containing c to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + -4c = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -4c = 0 + 1
-4c = 0 + 1

Combine like terms: 0 + 1 = 1
-4c = 1

Divide each side by '-4'.
c = -0.25

Simplifying
c = -0.25
Subproblem 2
Set the factor '(5 + -1c)' equal to zero and attempt to solve:

Simplifying
5 + -1c = 0

Solving
5 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + -1c = 0 + -5

Combine like terms: 5 + -5 = 0
0 + -1c = 0 + -5
-1c = 0 + -5

Combine like terms: 0 + -5 = -5
-1c = -5

Divide each side by '-1'.
c = 5

Simplifying
c = 5
Solution
c = {-0.25, 5}